中文

关于丢番图方程 $\displaystyle \sum _{k=1}^{5}F_{n_k}=2^a$

数论 2022-09-27 v2

摘要

(Fn)n0(F_n)_{n\geq 0} 为由 F0=0,F1=1F_0 = 0, F_1 = 1n0n \geq 0Fn+2=Fn+1+FnF_{n+2} = F_{n+1}+F_n 给出的斐波那契数列。本文中,我们确定了所有可表示为五个斐波那契数之和的 2 的幂,仅有少量我们已刻画的例外。我们还提出了一个与本文所研究此类方程的解的个数相关的开放问题。

关键词

引用

@article{arxiv.2209.07871,
  title  = {On the Diophantine equation $\displaystyle \sum _{k=1}^{5}F_{n_k}=2^a$},
  author = {Pagdame Tiebekabe and Ismaïla Diouf},
  journal= {arXiv preprint arXiv:2209.07871},
  year   = {2022}
}

备注

This article was presented at the 20th International Conference on Fibonacci Numbers and their Applications in Bosnia at the University of Sarajevo. arXiv admin note: substantial text overlap with arXiv:2202.10127