中文

由零积或Jordan零积作用刻画的自反代数上的映射

泛函分析 2011-06-23 v1

摘要

L\mathcal{L}为Banach空间XX上的子空间格,δ:AlgLB(X)\delta:\mathrm{Alg}\mathcal{L}\rightarrow B(X)为线性映射。若{LL:LL}=X\vee\{L\in \mathcal{L}: L_-\nsupseteq L\}=X{L:LL,LL}=(0)\wedge\{L_-:L\in \mathcal{L}, L_-\nsupseteq L\}=(0),我们证明以下三个条件等价:(1) 只要AB=0AB=0就有δ(AB)=δ(A)B+Aδ(B)\delta(AB)=\delta(A)B+A\delta(B);(2) 只要AB+BA=0AB+BA=0就有δ(AB+BA)=δ(A)B+Aδ(B)+δ(B)A+Bδ(A)\delta(AB+BA)=\delta(A)B+A\delta(B)+\delta(B)A+B\delta(A);(3) δ\delta是广义导子且δ(I)(AlgL)\delta(I)\in (\mathrm{Alg}\mathcal{L})^\prime。若{LL:LL}=X\vee\{L\in \mathcal{L}: L_-\nsupseteq L\}=X{L:LL,LL}=(0)\wedge\{L_-:L\in \mathcal{L}, L_-\nsupseteq L\}=(0),且δ\delta满足只要AB=0AB=0就有δ(AB+BA)=δ(A)B+Aδ(B)+δ(B)A+Bδ(A)\delta(AB+BA)=\delta(A)B+A\delta(B)+\delta(B)A+B\delta(A),我们得到δ\delta是广义导子且对每个AAlgLA\in \mathrm{Alg}\mathcal{L}δ(I)A(AlgL)\delta(I)A\in(\mathrm{Alg}\mathcal{L})^\prime。我们还证明,若{LL:LL}=X\vee\{L\in \mathcal{L}: L_-\nsupseteq L\}=X{L:LL,LL}=(0)\wedge\{L_-:L\in \mathcal{L}, L_-\nsupseteq L\}=(0),则δ\delta是局部广义导子当且仅当δ\delta是广义导子。

关键词

引用

@article{arxiv.1106.4371,
  title  = {Mappings on some reflexive algebras characterized by action on zero products or Jordan zero products},
  author = {Yunhe Chen and Jiankui Li},
  journal= {arXiv preprint arXiv:1106.4371},
  year   = {2011}
}

备注

12 pages