Collatz映射的一个近似及平均总停止时间的下界
动力系统
2024-08-14 v3 组合数学
数论
概率论
摘要
定义正整数上的映射T \mathsf{T} T :若m m m 为偶数,则T ( m ) = m 2 \mathsf{T}(m)=\frac{m}{2} T ( m ) = 2 m ;若m m m 为奇数,则T ( m ) = 3 m + 1 2 \mathsf{T}(m)=\frac{3m+1}{2} T ( m ) = 2 3 m + 1 。Terras和Everett的结果意味着,给定任意ϵ > 0 \epsilon>0 ϵ > 0 ,几乎所有m ∈ Z + m\in\mathbb{Z}^+ m ∈ Z + (在自然密度的意义上)对所有0 ≤ k ≤ α log m 0\leq k\leq \alpha\log m 0 ≤ k ≤ α log m (其中α = ( log 2 ) − 1 ≈ 1.443 \alpha=(\log 2)^{-1}\approx 1.443 α = ( log 2 ) − 1 ≈ 1.443 )同时满足( 3 2 ) k m 1 − ϵ ≤ T k ( m ) ≤ ( 3 2 ) k m 1 + ϵ (\frac{\sqrt{3}}{2})^km^{1-\epsilon}\leq \mathsf{T}^k(m)\leq (\frac{\sqrt{3}}{2})^km^{1+\epsilon} ( 2 3 ) k m 1 − ϵ ≤ T k ( m ) ≤ ( 2 3 ) k m 1 + ϵ 。我们将此结果扩展到α = 2 ( log 4 3 ) − 1 ≈ 6.952 \alpha=2(\log\frac{4}{3})^{-1}\approx 6.952 α = 2 ( log 3 4 ) − 1 ≈ 6.952 ,这是最大可能的值。设T min ( m ) : = min n ∈ N T n ( m ) \mathsf{T}_{\min}(m):=\min_{n\in\mathbb{N}}\mathsf{T}^n(m) T m i n ( m ) := min n ∈ N T n ( m ) 。作为一个直接推论,对于任意给定的ϵ > 0 \epsilon>0 ϵ > 0 ,几乎所有m ∈ Z + m\in\mathbb{Z}^+ m ∈ Z + 都有T min ( m ) ≤ T ⌊ 2 ( log 4 3 ) − 1 log m ⌋ ( m ) ≤ m ϵ \mathsf{T}_{\min}(m)\leq\mathsf{T}^{\left\lfloor2(\log\frac{4}{3})^{-1}\log m\right\rfloor}(m)\leq m^{\epsilon} T m i n ( m ) ≤ T ⌊ 2 ( l o g 3 4 ) − 1 l o g m ⌋ ( m ) ≤ m ϵ 。此前,Korec已证明,若ϵ > log 3 log 4 \epsilon>\frac{\log3}{\log4} ϵ > l o g 4 l o g 3 ,则对几乎所有m ∈ Z + m\in\mathbb{Z}^+ m ∈ Z + 有T min ( m ) ≤ m ϵ \mathsf{T}_{\min}(m)\leq m^\epsilon T m i n ( m ) ≤ m ϵ ;最近Tao证明了对所有发散到∞ \infty ∞ 的函数f f f ,对几乎所有m ∈ Z + m\in\mathbb{Z}^+ m ∈ Z + (在对数密度的意义上)有T min ( m ) ≤ f ( m ) \mathsf{T}_{\min}(m)\leq f(m) T m i n ( m ) ≤ f ( m ) 。用τ ( m ) \tau(m) τ ( m ) 表示使得T n ( m ) = 1 \mathsf{T}^n(m)=1 T n ( m ) = 1 的最小n ∈ N n\in\mathbb{N} n ∈ N (若存在这样的n n n ),否则设τ ( m ) = ∞ \tau(m)=\infty τ ( m ) = ∞ 。作为另一个应用,我们证明lim inf x → ∞ 1 x log x ∑ m = 1 ⌊ x ⌋ τ ( m ) ≥ 2 ( log 4 3 ) − 1 \liminf_{x\rightarrow\infty}\frac{1}{x\log x}\sum_{m=1}^{\lfloor x\rfloor}\tau(m)\geq 2(\log\frac{4}{3})^{-1} lim inf x → ∞ x l o g x 1 ∑ m = 1 ⌊ x ⌋ τ ( m ) ≥ 2 ( log 3 4 ) − 1 ,部分回答了Crandall和Shanks的一个问题。在假设Collatz猜想在强意义下成立(即τ ( m ) \tau(m) τ ( m ) 在O ( log m ) O(\log m) O ( log m ) 中)的条件下,我们证明lim x → ∞ 1 x log x ∑ m = 1 ⌊ x ⌋ τ ( m ) = 2 ( log 4 3 ) − 1 \lim_{x\rightarrow\infty}\frac{1}{x\log x}\sum_{m=1}^{\lfloor x\rfloor}\tau(m)= 2(\log\frac{4}{3})^{-1} lim x → ∞ x l o g x 1 ∑ m = 1 ⌊ x ⌋ τ ( m ) = 2 ( log 3 4 ) − 1 。
引用
@article{arxiv.2402.03276,
title = {An approximation of the Collatz map and a lower bound for the average total stopping time},
author = {Manuel Inselmann},
journal= {arXiv preprint arXiv:2402.03276},
year = {2024}
}
备注
New version with changes of exposition of results. An outline of proof of main result added. Approximation result for Syracuse map added. Further references added