中文

关于两平方和与一个2阶基

数论 2026-05-26 v4

摘要

R\mathcal{R} 表示可表示为 n=x2+y2n = x^2 + y^2(x,y)=1(x,y) = 1 的整数 nn 的集合。设 aabb 为整数,其中 a>0a>0aba \nmid b。我们证明,对于足够大的正整数 NN,存在两个连续正整数串 I1={n1m,,n1+m}I_{1}=\{n_1-m,\ldots, n_1+m\}I2={n2m,,n2+m}I_{2}=\{n_2-m, \ldots, n_2+m\},使得 m=[(logN)(loglogN)1/325565]m = [(\log N) (\log \log N)^{1/325565}]I1I2[1,N]I_{1}\cup I_{2} \subset [1, N]N=n1+n2N = n_1 + n_2,并且对于任何 nI1I2n\in I_{1}\cup I_{2}nnan+ban+b 中至少有一个不属于 R\mathcal{R}。特别地,对于所有 nI1I2n\in I_{1}\cup I_{2},我们有 n(an+b)Rn(an+b)\notin \mathcal{R}

关键词

引用

@article{arxiv.2604.20653,
  title  = {On sums of two squares and a basis of order $2$},
  author = {Artyom Radomskii},
  journal= {arXiv preprint arXiv:2604.20653},
  year   = {2026}
}

备注

35 pages. arXiv admin note: substantial text overlap with arXiv:2506.15641