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相关论文: Structure of (bull, diamond)-free graphs and its a…

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In this research, we determine the structure of (claw, bull)-free graphs. We show that every connected (claw, bull)-free graph is either an expansion of a path, an expansion of a cycle, or the complement of a triangle-free graph; where an…

The bull is a graph consisting of a triangle and two pendant edges. The P_5 is the chordless path on five vertices. The house is the complement of a P_5. A graph is k-critical if it is k-chromatic but each of its proper induced subgraphs is…

组合数学 · 数学 2026-05-19 Manoj Belavadi , Chinh T. Hoang

A graph $G = (V, E)$ is \emph{partitionable} if there exists a partition $\{A, B\}$ of $V$ such that $A$ induces a disjoint union of cliques and $B$ induces a triangle-free graph. In this paper we investigate the computational complexity of…

计算复杂性 · 计算机科学 2015-01-06 Faisal N. Abu-Khzam , Carl Feghali , Haiko Müller

Let $G$ be a graph. We use $P_t$ and $C_t$ to denote a path and a cycle on $t$ vertices, respectively. A {\em diamond} is a graph obtained from two triangles that share exactly one edge. A {\em kite} is a graph consists of a diamond and…

组合数学 · 数学 2023-02-23 Ran Chen , Di Wu , Baogang Xu

Motivated by Chudnovsky's structure theorem of bull-free graphs, Abu-Khzam, Feghali, and M\"uller have recently proved that deciding if a graph has a vertex partition into disjoint cliques and a triangle-free graph is NP-complete for five…

离散数学 · 计算机科学 2015-12-08 Marin Bougeret , Pascal Ochem

A bull is a graph obtained from a four-vertex path by adding a vertex adjacent to the two middle vertices of the path. A graph $G$ is bull-free if no induced subgraph of $G$ is a bull. We prove that for all $k,t\in \mathbb{N}$, if $G$ is a…

组合数学 · 数学 2025-06-13 Sepehr Hajebi

The $3$-colourability problem is a well-known NP-complete problem and it remains NP-complete for $bull$-free graphs, where $bull$ is the graph consisting of $K_3$ with two pendant edges attached to two of its vertices. In this paper we…

组合数学 · 数学 2024-04-22 Nadzieja Hodur , Monika Pilśniak , Magdalena Prorok , Ingo Schiermeyer

The $3$-colorability problem is a well-known NP-complete problem and it remains NP-complete for $(claw, diamond, K_4)$-free graphs. Recently, $3$-colorability has been also considered for $(claw, N_{1,1,1})$-free graphs. Here, a generalised…

组合数学 · 数学 2026-02-10 Nadzieja Hodur , Monika Pilśniak , Magdalena Prorok , Ingo Schiermeyer

In this paper, we are interested in $4$-colouring algorithms for graphs that do not contain an induced path on $6$ vertices nor an induced bull, i.e., the graph with vertex set $\{v_1,v_2,v_3,v_4,v_5\}$ and edge set…

组合数学 · 数学 2025-04-22 Yiao Ju , Jorik Jooken , Jan Goedgebeur , Shenwei Huang

A graph is called (claw,diamond)-free if it contains neither a claw (a $K_{1,3}$) nor a diamond (a $K_4$ with an edge removed) as an induced subgraph. Equivalently, (claw,diamond)-free graphs can be characterized as line graphs of…

数据结构与算法 · 计算机科学 2015-03-03 Marek Cygan , Marcin Pilipczuk , Michał Pilipczuk , Erik Jan van Leeuwen , Marcin Wrochna

A diamond is the graph that is obtained from removing an edge from the complete graph on $4$ vertices. A ($C_4$,diamond)-free graph is a graph that does not contain a diamond or a cycle on four vertices as induced subgraphs. Let $G$ be a…

组合数学 · 数学 2022-08-01 Ruy Fabila-Monroy , Ana Laura Trujillo-Negrete

We present a polynomial-time algorithm that determines whether a graph that contains no induced path on six vertices and no bull (the graph with vertices a, b, c, d, e and edges ab, bc, cd, be, ce) is 4-colorable. We also show that for any…

组合数学 · 数学 2016-02-25 Frédéric Maffray , Lucas Pastor

A graph is probe diamond-free if its vertex set admits a partition into probes and nonprobes, where the set of nonprobes is independent, such that adding edges only between pairs of nonprobes yields a diamond-free graph. Although this class…

组合数学 · 数学 2026-05-19 Luciano Norberto Grippo Min Chih Lin

A graph $G$ is {\em perfectly divisible} if, for each induced subgraph $H$ of $G$, $V(H)$ can be partitioned into $A$ and $B$ such that $H[A]$ is perfect and $\omega(H[B])<\omega(H)$. A {\em bull} is a graph consisting of a triangle with…

组合数学 · 数学 2026-03-24 Ran Chen , Paras Vinubhai Maniya , Di Wu , Junran Yu

A hole is a chordless cycle with at least four vertices. A hole is odd if it has an odd number of vertices. A dart is a graph which vertices $a, b, c, d, e$ and edges $ab, bc, bd, be, cd, de$. Dart-free graphs have been actively studied in…

组合数学 · 数学 2025-04-30 Chính T. Hoàng

A graph is $\mathrm{ISK}_4$-free if it contains no induced subdivision of $K_4$. L\'ev\^eque et al. [\emph{J. Combin. Theory Ser. B} \textbf{102} (2012) 924--947] conjectured that all $\mathrm{ISK}_4$-free graphs are 4-colorable. Chen et…

组合数学 · 数学 2026-03-20 Feng Liu , Shuang Sun , Yan Wang

A natural way of increasing our understanding of NP-complete graph problems is to restrict the input to a special graph class. Classes of $H$-free graphs, that is, graphs that do not contain some graph $H$ as an induced subgraph, have…

数据结构与算法 · 计算机科学 2022-04-19 Christoph Brause , Petr Golovach , Barnaby Martin , Daniël Paulusma , Siani Smith

We give a polynomial-time algorithm that computes the chromatic number of any graph that contains no path on five vertices and no bull as an induced subgraph (where the bull is the graph with five vertices $a,b,c,d,e$ and edges…

组合数学 · 数学 2017-07-28 Frédéric Maffray

The diamond is the graph obtained by removing an edge from the complete graph on 4 vertices. A graph is ($P_6$, diamond)-free if it contains no induced subgraph isomorphic to a six-vertex path or a diamond. In this paper we show that the…

组合数学 · 数学 2021-06-17 Jan Goedgebeur , Shenwei Huang , Yiao Ju , Owen Merkel

The $3$-colorability problem is a well-known NP-complete problem and it remains NP-complete for $bull$-free graphs, where a $bull$ is the graph consisting of a $K_3$ with two pendant edges attached to two of its vertices. In this paper, for…

组合数学 · 数学 2025-09-03 Nadzieja Hodur , Monika Pilśniak , Magdalena Prorok , Ingo Schiermeyer
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