中文

由旋转诱导的$\Hol(\D)$上加权复合算子的谱性质

泛函分析 2021-08-19 v1

摘要

本文研究了由旋转诱导的\Hol(\D)\Hol(\D)上加权复合算子TT的谱σ(T)\sigma(T)与Waelbroeck谱σW(T)\sigma_W(T),其定义为Tf(z)=m(z)f(βz)   (z\D)Tf(z)=m(z)f(\beta z) \ \ \ (z\in \D)其中m\Hol(\D)m\in \Hol(\D)β\C\beta\in \Cβ=1|\beta | = 1。若对所有nNn\in \Nβn1\beta^n\neq 1,我们证明:若存在某z0\Dz_0\in \D使m(z0)=0m(z_0)=0,则σW(T)\sigma_W(T)为一个圆盘;若对所有z\Dz\in \Dm(z)0m(z)\neq 0,则其为圆周{λ\C:λ=m(0)}\{\lambda\in \C : |\lambda |=|m(0)|\}。我们找到了mA(\D)m\in A(\D)(圆盘代数)的实例,使得λ\IdT\lambda\Id-T\Hol(\D)\Hol(\D)(\D上所有全纯函数构成的Fr\'echet空间)中可逆,但(λ\IdT)1A(\D)⊄A(\D)(\lambda\Id-T)^{-1}A(\D)\not\subset A(\D)。受Bonet \cite{Bonet}启发,我们证明了当权函数为m1m\equiv 1β\beta为丢番图数时,{βn:nN}σ(T)\T\{\beta^n : n\in \N\}\subset \sigma(T)\neq \T。这表明谱一般而言并不闭。

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引用

@article{arxiv.2108.08270,
  title  = {Spectral properties of weighted composition operators on $\Hol(\D)$ induced by rotations},
  author = {W. Arendt and E. Bernard and B. Célariès and I. Chalendar},
  journal= {arXiv preprint arXiv:2108.08270},
  year   = {2021}
}