中文

An elementary proof that random Fibonacci sequences grow exponentially

数论 2007-05-23 v2

摘要

We consider random Fibonacci sequences given by xn+1=±βxn+xn1x_{n+1}=\pm \beta x_{n}+x_{n-1}. Viswanath (\cite{viswanath}), following Furstenberg (\cite{furst}) showed that when β=1\beta = 1, limnxn1/n=1.13...\lim_{n\to \infty}|x_{n}|^{1/n}=1.13..., but his proof involves the use of floating point computer calculations. We give a completely elementary proof that 1.25577(E(xn))1/n1.120951.25577 \ge (E(|x_{n}|))^{1/n} \ge 1.12095 where E(xn)E(|x_{n}|) is the expected value for the absolute value of the nnth term in a random Fibonacci sequence. We compute this expected value using recurrence relations which bound the sum of all possible nnth terms for such sequences. In addition, we give upper an lower

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引用

@article{arxiv.math/0510159,
  title  = {An elementary proof that random Fibonacci sequences grow exponentially},
  author = {Eran Makover and Jeffrey McGowan},
  journal= {arXiv preprint arXiv:math/0510159},
  year   = {2007}
}

备注

7 pages, 2 figures