中文

关于丢番图方程1/a + 1/b = (q+1) / pq

历史与综述 2019-05-09 v1 数论

摘要

ppqq为互异素数且满足q+1p1q+1 | p-1。本文仅用初等方法求出方程1/a+1/b=(q+1)/pq1/a + 1/b = (q+1)/pq的所有整数解aabb

关键词

引用

@article{arxiv.1905.03056,
  title  = {On the Diophantine Equation 1/a + 1/b = (q+1) / pq},
  author = {Jeremiah W. Johnson},
  journal= {arXiv preprint arXiv:1905.03056},
  year   = {2019}
}