A note on primes dividing alternating sums
综合数学
2007-05-23 v1
摘要
We define A_n=\sum_{i=1}^n (-1)^i\frac{1}{i} and we show that, for every prime p, there exists a number n such that A_n\equiv 0 (mod p).
引用
@article{arxiv.math/0607491,
title = {A note on primes dividing alternating sums},
author = {Antonio M. Oller Marcen},
journal= {arXiv preprint arXiv:math/0607491},
year = {2007}
}