中文

几类解析单叶函数的支撑点

复变函数 2022-09-23 v1

摘要

A\mathcal{A}表示单位圆盘D:={zC:z<1}\mathbb{D}:=\{z\in\mathbb{C}:|z|<1\}内满足f(0)=0f(0)=0f(0)=1f'(0)=1的解析函数类。令U\mathcal{U}为满足f(z)(zf(z))21<1\mboxforzD,\left|f'(z)\left(\frac{z}{f(z)}\right)^2-1 \right|< 1 \quad\mbox{ for } z\in\mathbb{D},fAf\in\mathcal{A}之函数类,并令G\mathscr{G}表示满足Re(1+zf(z)f(z))>12\mboxforzD.{\rm Re\,}\left(1+\frac{zf''(z)}{f'(z)}\right)>-\frac{1}{2} \quad\mbox{ for } z\in\mathbb{D}.fAf\in \mathcal{A}之函数类。

关键词

引用

@article{arxiv.2209.10607,
  title  = {Support points of some classes of analytic and univalent functions},
  author = {Vasudevarao Allu and Abhishek Pandey},
  journal= {arXiv preprint arXiv:2209.10607},
  year   = {2022}
}

备注

10 pages