中文

基于周期分布傅里叶级数的一种求和法及实例

泛函分析 2020-03-31 v6 复变函数

摘要

考虑了一种基于周期分布傅里叶级数的广义求和法。证明了eit2e2it+3e3it4e4it+=Pfeit(1+eit)2+iπnZδ(2n+1)π, e^{it}-2e^{2it}+3e^{3it}-4e^{4it}+-\cdots = {\mathrm P\mathrm f} {\displaystyle \frac{e^{it}}{(1+e^{it})^2}} +i\pi \displaystyle \sum_{n\in \mathbb{Z}} \delta'_{(2n+1)\pi}, 其中Pfeit(1+eit)2D(R){\mathrm P\mathrm f} {\displaystyle \frac{e^{it}}{(1+e^{it})^2}}\in \mathcal{D}'(\mathbb{R})是由\begin{eqnarray*} \left\langle {\mathrm P\mathrm f} {\displaystyle \frac{e^{it}}{(1+e^{it})^2}} ,\varphi \right\rangle &=& \lim_{\epsilon\searrow 0} \left( \int_{(-\delta,\pi-\epsilon)\cup(\pi+\epsilon,2\pi+\delta)}\frac{\varphi(t) e^{it}}{(1+e^{it})^2}dt -\frac{\varphi(\pi)}{\tan (\epsilon/2)}\right) \end{eqnarray*} \varphi \in \mathcal{D}(\mathbb{R})且支集且支集\textrm{supp}(\varphi)\subset (-\delta,2\pi+\delta),其中,其中\delta\in (0,\pi)给出的给出的2\pi周期分布。应用该广义求和法,我们确定了发散级数周期分布。应用该广义求和法,我们确定了发散级数1+2+3+\cdots以及更一般地以及更一般地k\in \mathbb{N}1^k+2^k+3^k+\cdots$的和。

关键词

引用

@article{arxiv.1905.03000,
  title  = {A summation method based on the Fourier series of periodic distributions and an example},
  author = {Amol Sasane},
  journal= {arXiv preprint arXiv:1905.03000},
  year   = {2020}
}

备注

31 pages, 5 figures (Typos corrected.)