中文

Peg Jumping for Fun and Profit

组合数学 2007-05-23 v2

摘要

We consider the problem of determining the minimum number of moves needed to solve a certain one-dimensional peg puzzle. Let N be a positive integer. The puzzle apparatus consists of a block with a single row of 2N+1 equally spaced holes which, apart from the central hole, are occupied by an equal number N of red and blue pegs. The object of the puzzle is to exchange the colors of the pegs by a succession of allowable moves. Allowable moves are of two types: a peg can be shifted from the hole it occupies into the empty hole adjacent to it, or a peg can jump over an adjacent peg into the empty hole. We exhibit a sequence of N^2+2N moves that solves the puzzle, and prove that no solution can employ fewer moves.

关键词

引用

@article{arxiv.math/0411275,
  title  = {Peg Jumping for Fun and Profit},
  author = {David M. Bradley and Hugh Thomas},
  journal= {arXiv preprint arXiv:math/0411275},
  year   = {2007}
}

备注

Original: 7 pages, recreational mathematics. Replacement: 6 pages, 6 figures, conjectured lower bound proved, retitled