中文

形如$k+f(k)$的数

数论 2023-06-29 v1

摘要

对于函数f ⁣:NNf\colon \mathbb{N}\to\mathbb{N},令 Nf+(x)={nx:n=k+f(k)\mbox对某个k}. N^+_f(x)=\{n\leq x: n=k+f(k) \mbox{ 对某个 } k\}. τ(n)=dn1\tau(n)=\sum_{d|n}1为除数函数,ω(n)=pn1\omega(n)=\sum_{p|n}1为素因子个数函数,φ(n)=#{1kn:gcd(k,n)=1}\varphi(n)=\#\{1\leq k\leq n: \gcd(k,n)=1 \}为欧拉 totient 函数。我们证明 \begin{align*} &(1) \quad x \ll N^+_{\omega}(x), \\ &(2) \quad x\ll N^+_{\tau}(x) \leq 0.94x, \\ &(3) \quad x \ll N^+_{\varphi}(x) \leq 0.93x. \end{align*}

关键词

引用

@article{arxiv.2306.16035,
  title  = {Numbers of the form $k+f(k)$},
  author = {Mikhail R. Gabdullin and Vitalii V. Iudelevich and Florian Luca},
  journal= {arXiv preprint arXiv:2306.16035},
  year   = {2023}
}