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相关论文: Scott ranks of models of a theory

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We calculate the possible Scott ranks of countable models of Peano arithmetic. We show that no non-standard model can have Scott rank less than $\omega$ and that non-standard models of true arithmetic must have Scott rank greater than…

逻辑 · 数学 2022-08-04 Antonio Montalbán , Dino Rossegger

We demonstrate that any $\Pi_\alpha$ sentence of the infinitary logic $L_{\omega_1 \omega}$ extending the theory of linear orderings has a model with a $\Pi_{\alpha+4}$ Scott sentence and hence of Scott rank at most $\alpha+3$. In other…

逻辑 · 数学 2025-05-02 David Gonzalez , Matthew Harrison-Trainor

We give a notion of Scott rank for separable metric structures based on the definability of the (metric closures of) automorphism orbits in continuous infinitary logic. This is a continuous analogue of work of Montalb\'an for countable…

逻辑 · 数学 2024-11-05 Diego Bejarano

Every countable structure has a sentence of the infinitary logic $\mathcal{L}_{\omega_1 \omega}$ which characterizes that structure up to isomorphism among countable structures. Such a sentence is called a Scott sentence, and can be thought…

逻辑 · 数学 2020-11-10 Matthew Harrison-Trainor

We give several new examples of computable structures of high Scott rank. For earlier known computable structures of Scott rank $\omega_1^{CK}$, the computable infinitary theory is $\aleph_0$-categorical. Millar and Sacks asked whether this…

逻辑 · 数学 2016-06-06 Matthew Harrison-Trainor , Gregory Igusa , Julia F. Knight

Given a countable mathematical structure, its Scott sentence is a sentence of the infinitary logic $\mathcal{L}_{\omega_1 \omega}$ that characterizes it among all countable structures. We can measure the complexity of a structure by the…

逻辑 · 数学 2025-11-07 Rachael Alvir , Barbara Csima , Matthew Harrison-Trainor

Given a Borel class of trees, we show that there is a tree in that class whose Scott sentence is not too much more complicated than the definition of the class. In particular, if the class is definable by a $\Pi_\alpha$ sentence, then there…

逻辑 · 数学 2026-02-23 Matthew Harrison-Trainor , J. Thomas Kim

It is well-known that the first order Peano axioms PA have a continuum of non-isomorphic countable models. The question, how close to being isomorphic such countable models can be, seems to be less investigated. A measure of closeness to…

逻辑 · 数学 2022-08-30 Tapani Hyttinen , Jouko Väänänen

There are familiar examples of computable structures having various computable Scott ranks. There are also familiar structures, such as the Harrison ordering, which have Scott rank $\omega_1^{CK}+1$. Makkai produced a structure of Scott…

逻辑 · 数学 2008-03-25 Wesley Calvert , Sergey S. Goncharov , Julia F. Knight

A rank is a notion in descriptive set theory that describes ranks such as the Cantor-Bendixson rank on the set of closed subsets of a Polish space, differentiability ranks on the set of differentiable functions in $C[0,1]$ such as the…

逻辑 · 数学 2022-07-19 Merlin Carl , Philipp Schlicht , Philip Welch

If $\mathcal{N}$ is a proper Polish metric space and $\mathcal{M}$ is any countable dense submetric space of $\mathcal{N}$, then the Scott rank of $\mathcal{N}$ in the natural first order language of metric spaces is countable and in fact…

逻辑 · 数学 2019-06-12 William Chan

We study the complexity of automatic structures via well-established concepts from both logic and model theory, including ordinal heights (of well-founded relations), Scott ranks of structures, and Cantor-Bendixson ranks (of trees). We…

逻辑 · 数学 2008-09-22 Bakhadyr Khoussainov , Mia Minnes

We study the usual notion of Scott rank but in the setting of Polish metric spaces. The signature consists of distance relations: for each rational $q > 0$, there is a relation $R_{<q}(x,y)$ stating that the distance of $x$ and $y $ is less…

度量几何 · 数学 2019-06-04 Sy Friedman , Katia Fokina , Martin Koerwien , Andre Nies

The goal of this paper is to show there is a single orbit of the c.e. sets with inclusion, $\mathcal{E}$, such that the question of membership in this orbit is $\Sigma^1_1$-complete. This result and proof have a number of nice corollaries:…

逻辑 · 数学 2007-11-21 Peter Cholak , Rod Downey , Leo Harrington

Given a countable scattered linear order $L$ of Hausdorff rank $\alpha < \omega_1$ we show that it has a $d\text{-}\Sigma_{2\alpha+1}$ Scott sentence. Ash calculated the back and forth relations for all countable well-orders. From this…

逻辑 · 数学 2021-07-01 Rachael Alvir , Dino Rossegger

Scott showed that for every countable structure $\mathcal{A}$, there is a sentence of the infinitary logic $\mathcal{L}_{\omega_1\omega}$, called a Scott sentence for $\mathcal{A}$, whose models are exactly the isomorphic copies of…

逻辑 · 数学 2017-02-22 Matthew Harrison-Trainor , Meng-Che Ho

Using new techniques for controlling the categoricity spectrum of a structure, we construct a structure with degree of categoricity but infinite spectral dimension, answering a question of Bazhenov, Kalimulin and Yamaleev. Using the same…

逻辑 · 数学 2020-01-29 Dan Turetsky

The goal of this paper is to announce there is a single orbit of the c.e. sets with inclusion, $\E$, such that the question of membership in this orbit is $\Sigma^1_1$-complete. This result and proof have a number of nice corollaries: the…

逻辑 · 数学 2015-05-13 Peter A. Cholak , Rod Downey , Leo Harrington

We take two approaches to classifying the complexity of Presburger models: Scott analysis and degree spectra. In particular, we investigate the possible Scott sentence complexities and possible degree spectra of models of Presburger…

逻辑 · 数学 2026-03-19 Jason Block

Friedman and Stanley developed the notion of Borel reducibility and illustrated its use in comparing classification problems for some familiar classes of countable structures. For many embeddings, the fact that the embedding is $1-1$ on…

逻辑 · 数学 2026-05-07 David Gonzalez , Julia Knight
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