English

On perfect powers that are sums of cubes of a nine term arithmetic progression

Number Theory 2023-09-20 v3

Abstract

We study the equation (x4r)3+(x3r)3+(x2r)3+(xr)3+x3+(x+r)3+(x+2r)3+(x+3r)3+(x+4r)3=yp(x-4r)^3 + (x-3r)^3 + (x-2r)^3+(x-r)^3 + x^3 + (x+r)^3+(x+2r)^3 + (x+3r)^3 + (x+4r)^3 = y^p, which is a natural continuation of previous works carried out by A. Arg\'{a}ez-Garc\'{i}a and the fourth author (perfect powers that are sums of cubes of a three, five and seven term arithmetic progression). Under the assumptions 0<r1060 < r \leq 10^6, p5p \geq 5 a prime and gcd(x,r)=1\gcd(x, r) = 1, we show that solutions must satisfy xy=0xy=0. Moreover, we study the equation for prime exponents 22 and 33 in greater detail. Under the assumptions r>0r>0 a positive integer and gcd(x,r)=1\gcd(x, r) = 1 we show that there are infinitely many solutions for p=2p=2 and p=3p=3 via explicit constructions using integral points on elliptic curves. We use an amalgamation of methods in computational and algebraic number theory to overcome the increased computational challenge. Most notable is a significant computational efficiency obtained through appealing to Bilu, Hanrot and Voutier's Primitive Divisor Theorem and the method of Chabauty, as well as employing a Thue equation solver earlier on.

Keywords

Cite

@article{arxiv.2307.01815,
  title  = {On perfect powers that are sums of cubes of a nine term arithmetic progression},
  author = {Nirvana Coppola and Mar Curcó-Iranzo and Maleeha Khawaja and Vandita Patel and Özge Ülkem},
  journal= {arXiv preprint arXiv:2307.01815},
  year   = {2023}
}

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12 pages