English

Sum of consecutive powers as a perfect power

Number Theory 2026-05-19 v1

Abstract

In this paper we study the equation xk+(x+1)k=yn,n3, x^k + (x+1)^k = y^n,\quad n\geq 3, when k2(mod4)k\equiv 2\pmod{4}. We prove that the only solutions are for x=0,1x=0, -1 when 6k1006\leq k\leq 100 or for a kk with odd prime factors congruent to 3(mod4)3\pmod{4}. We use linear forms in logarithms, the modular method and the resolution of Thue equations.

Keywords

Cite

@article{arxiv.2605.18348,
  title  = {Sum of consecutive powers as a perfect power},
  author = {Angelos Koutsianas and Nikos Tzanakis},
  journal= {arXiv preprint arXiv:2605.18348},
  year   = {2026}
}

Comments

17 pages; Comments are welcome