English

Perfect powers in alternating sum of consecutive cubes

Number Theory 2017-05-12 v2

Abstract

In this paper, we consider the problem about finding out perfect powers in an alternating sum of consecutive cubes. More precisely, we completely solve the Diophantine equation (x+1)3(x+2)3+(x+2d)3+(x+2d+1)3=zp(x+1)^3 - (x+2)^3 + \cdots - (x + 2d)^3 + (x + 2d + 1)^3 = z^p, where pp is prime and x,d,zx,d,z are integers with 1d501 \leq d \leq 50.

Keywords

Cite

@article{arxiv.1705.02597,
  title  = {Perfect powers in alternating sum of consecutive cubes},
  author = {Pranabesh Das and Pallab Kanti Dey and B. Maji and S. S. Rout},
  journal= {arXiv preprint arXiv:1705.02597},
  year   = {2017}
}
R2 v1 2026-06-22T19:39:25.973Z