Sums of two cubes as twisted perfect powers, revisited
Number Theory
2017-02-28 v1
Abstract
In this paper, we sharpen earlier work of the first author, Luca and Mulholland, showing that the Diophantine equation has, for "most" primes and suitably large prime exponents , no solutions. We handle a number of (presumably infinite) families where no such conclusion was hitherto known. Through further application of certain {\it symplectic criteria}, we are able to make some conditional statements about still more values of , a sample such result is that, for all but primes up to , the equation has no solutions in coprime, nonzero integers and , for a positive proportion of prime exponents .
Cite
@article{arxiv.1702.07827,
title = {Sums of two cubes as twisted perfect powers, revisited},
author = {Michael A. Bennett and Carmen Bruni and Nuno Freitas},
journal= {arXiv preprint arXiv:1702.07827},
year = {2017}
}