English

Sums of two cubes as twisted perfect powers, revisited

Number Theory 2017-02-28 v1

Abstract

In this paper, we sharpen earlier work of the first author, Luca and Mulholland, showing that the Diophantine equation A3+B3=qαCp,ABC0,gcd(A,B)=1, A^3+B^3 = q^\alpha C^p, \, \, ABC \neq 0, \, \, \gcd (A,B) =1, has, for "most" primes qq and suitably large prime exponents pp, no solutions. We handle a number of (presumably infinite) families where no such conclusion was hitherto known. Through further application of certain {\it symplectic criteria}, we are able to make some conditional statements about still more values of qq, a sample such result is that, for all but O(x/logx)O(\sqrt{x}/\log x) primes qq up to xx, the equation A3+B3=qCp. A^3 + B^3 = q C^p. has no solutions in coprime, nonzero integers A,BA, B and CC, for a positive proportion of prime exponents pp.

Keywords

Cite

@article{arxiv.1702.07827,
  title  = {Sums of two cubes as twisted perfect powers, revisited},
  author = {Michael A. Bennett and Carmen Bruni and Nuno Freitas},
  journal= {arXiv preprint arXiv:1702.07827},
  year   = {2017}
}