English

On perfect powers that are sums of cubes of a seven term arithmetic progression

Number Theory 2019-11-06 v1

Abstract

We prove that the equation (x3r)3+(x2r)3+(xr)3+x3+(x+r)3+(x+2r)3+(x+3r)3=yp(x-3r)^3+(x-2r)^3 + (x-r)^3 + x^3 + (x+r)^3 + (x+2r)^3+(x+3r)^3= y^p only has solutions which satisfy xy=0xy=0 for 1r1061\leq r\leq 10^6 and p5p\geq 5 prime. This article complements the work on the equations (xr)3+x3+(x+r)3=yp(x-r)^3 + x^3 + (x+r)^3 = y^p and (x2r)3+(xr)3+x3+(x+r)3+(x+2r)3=yp(x-2r)^3 + (x-r)^3 + x^3 + (x+r)^3 + (x+2r)^3= y^p . The methodology in this paper makes use of the Primitive Divisor Theorem due to Bilu, Hanrot and Voutier for a complete resolution of the Diophantine equation.

Keywords

Cite

@article{arxiv.1911.01842,
  title  = {On perfect powers that are sums of cubes of a seven term arithmetic progression},
  author = {Alejandro Argáez-García and Vandita Patel},
  journal= {arXiv preprint arXiv:1911.01842},
  year   = {2019}
}

Comments

arXiv admin note: text overlap with arXiv:1901.05382