English

Noether's Problem on Semidirect Product Groups

Commutative Algebra 2017-04-25 v1

Abstract

Let KK be a field, GG a finite group. Let GG act on the function field L=K(xσ:σG)L = K(x_{\sigma} : \sigma \in G) by τxσ=xτσ\tau \cdot x_{\sigma} = x_{\tau\sigma} for any σ,τG\sigma, \tau \in G. Denote the fixed field of the action by K(G)=LG={fgL:σ(fg)=fg,σG}K(G) = L^{G} = \left\{ \frac{f}{g} \in L : \sigma(\frac{f}{g}) = \frac{f}{g}, \forall \sigma \in G \right\}. Noether's problem asks whether K(G)K(G) is rational (purely transcendental) over KK. It is known that if G=CmCnG = C_m \rtimes C_n is a semidirect product of cyclic groups CmC_m and CnC_n with Z[ζn]\mathbb{Z}[\zeta_n] a unique factorization domain, and KK contains an eeth primitive root of unity, where ee is the exponent of GG, then K(G)K(G) is rational over KK. In this paper, we give another criteria to determine whether K(CmCn)K(C_m \rtimes C_n) is rational over KK. In particular, if p,qp, q are prime numbers and there exists xZ[ζq]x \in \mathbb{Z}[\zeta_q] such that the norm NQ(ζq)/Q(x)=pN_{\mathbb{Q}(\zeta_q)/\mathbb{Q}}(x) = p, then C(CpCq)\mathbb{C}(C_{p} \rtimes C_{q}) is rational over C\mathbb{C}.

Keywords

Cite

@article{arxiv.1704.07053,
  title  = {Noether's Problem on Semidirect Product Groups},
  author = {Huah Chu and Shang Huang},
  journal= {arXiv preprint arXiv:1704.07053},
  year   = {2017}
}
R2 v1 2026-06-22T19:25:17.065Z