English

$q$-Analogues of some supercongruences related to Euler numbers

Number Theory 2020-10-27 v1 Combinatorics

Abstract

Let EnE_n be the nn-th Euler number and (a)n=a(a+1)(a+n1)(a)_n=a(a+1)\cdots (a+n-1) the rising factorial. Let p>3p>3 be a prime. In 2012, Sun proved the that k=0(p1)/2(1)k(4k+1)(12)k3k!3p(1)(p1)/2+p3Ep3(modp4), \sum^{(p-1)/2}_{k=0}(-1)^k(4k+1)\frac{(\frac{1}{2})_k^3}{k!^3} \equiv p(-1)^{(p-1)/2}+p^3E_{p-3} \pmod{p^4}, which is a refinement of a famous supercongruence of Van Hamme. In 2016, Chen, Xie, and He established the following result: k=0p1(1)k(3k+1)(12)k3k!323kp(1)(p1)/2+p3Ep3(modp4), \sum_{k=0}^{p-1}(-1)^k (3k+1)\frac{(\frac{1}{2})_k^3}{k!^3} 2^{3k} \equiv p(-1)^{(p-1)/2}+p^3E_{p-3} \pmod{p^4}, which was originally conjectured by Sun. In this paper we give qq-analogues of the above two supercongruences by employing the qq-WZ method. As a conclusion, we provide a qq-analogue of the following supercongruence of Sun: k=0(p1)/2(12)k2k!2(1)(p1)/2+p2Ep3(modp3). \sum_{k=0}^{(p-1)/2}\frac{(\frac{1}{2})_k^2}{k!^2} \equiv (-1)^{(p-1)/2}+p^2 E_{p-3} \pmod{p^3}.

Keywords

Cite

@article{arxiv.2010.13526,
  title  = {$q$-Analogues of some supercongruences related to Euler numbers},
  author = {Victor J. W. Guo},
  journal= {arXiv preprint arXiv:2010.13526},
  year   = {2020}
}

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12 pages