English

New super congruences involving Bernoulli and Euler polynomials

Number Theory 2016-05-31 v1 Combinatorics

Abstract

Let p>3p>3 be a prime, and let aa be a rational p-adic integer with a≢0(modp)a\not\equiv 0\pmod p. In this paper we establish congruences for k=1(p1)/2(ak)(1ak)k,k=0(p1)/2k(ak)(1ak)andk=0(p1)/2(ak)(1ak)2k1(modp2)\sum_{k=1}^{(p-1)/2}\frac{\binom ak\binom{-1-a}k}k, \quad\sum_{k=0}^{(p-1)/2}k\binom ak\binom{-1-a}k \quad\text{and}\quad\sum_{k=0}^{(p-1)/2}\frac{\binom ak\binom{-1-a}k}{2k-1}\pmod {p^2} in terms of Bernoulli and Euler polynomials. We also give some transformation formulas for congruences modulo p2p^2.

Keywords

Cite

@article{arxiv.1605.09179,
  title  = {New super congruences involving Bernoulli and Euler polynomials},
  author = {Zhi-Hong Sun},
  journal= {arXiv preprint arXiv:1605.09179},
  year   = {2016}
}

Comments

20 pages

R2 v1 2026-06-22T14:12:45.552Z