English

On the number of spanning trees a planar graph can have

Combinatorics 2010-09-07 v2

Abstract

We prove that any planar graph on nn vertices has less than O(5.2852n)O(5{.}2852^n) spanning trees. Under the restriction that the planar graph is 3-connected and contains no triangle and no quadrilateral the number of its spanning trees is less than O(2.7156n)O(2{.}7156^n). As a consequence of the latter the grid size needed to realize a 3d polytope with integer coordinates can be bounded by O(147.7n)O(147.{7}^n). Our observations imply improved upper bounds for related quantities: the number of cycle-free graphs in a planar graph is bounded by O(6.4884n)O(6.4884^n), the number of plane spanning trees on a set of nn points in the plane is bounded by O(158.6n)O(158.6^n), and the number of plane cycle-free graphs on a set of nn points in the plane is bounded by O(194.7n)O(194{.}7^n).

Keywords

Cite

@article{arxiv.0912.0712,
  title  = {On the number of spanning trees a planar graph can have},
  author = {Kevin Buchin and André Schulz},
  journal= {arXiv preprint arXiv:0912.0712},
  year   = {2010}
}

Comments

Computations in Mathematica included as supplemental material