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New Hardness Results in Rainbow Connectivity

Computational Complexity 2011-04-13 v1 Discrete Mathematics Combinatorics

Abstract

A path in an edge colored graph is said to be a rainbow path if no two edges on the path have the same color. An edge colored graph is (strongly) rainbow connected if there exists a (geodesic) rainbow path between every pair of vertices. The (strong) rainbow connectivity of a graph GG, denoted by (src(G)src(G), respectively) rc(G)rc(G) is the smallest number of colors required to edge color the graph such that the graph is (strong) rainbow connected. It is known that for \emph{even} kk to decide whether the rainbow connectivity of a graph is at most kk or not is NP-hard. It was conjectured that for all kk, to decide whether rc(G)krc(G) \leq k is NP-hard. In this paper we prove this conjecture. We also show that it is NP-hard to decide whether src(G)ksrc(G) \leq k or not even when GG is a bipartite graph.

Keywords

Cite

@article{arxiv.1104.2074,
  title  = {New Hardness Results in Rainbow Connectivity},
  author = {Prabhanjan Ananth and Meghana Nasre},
  journal= {arXiv preprint arXiv:1104.2074},
  year   = {2011}
}

Comments

15 pages, 2 figures

R2 v1 2026-06-21T17:52:37.563Z