English

Congruences for $q^{[p/8]}\pmod p$ II

Number Theory 2014-01-03 v1

Abstract

Let Z\Bbb Z be the set of integers, and let pp be a prime of the form 4k+14k+1. Suppose qZq\in\Bbb Z, 2q2\nmid q, pqp\nmid q, p=c2+d2p=c^2+d^2, c,dZc,d\in\Bbb Z and c1(mod4)c\equiv 1\pmod 4. In this paper we continue to discuss congruences for q[p/8](modp)q^{[p/8]}\pmod p and present new reciprocity laws, but we assume 4p=x2+qy24p=x^2+qy^2 or p=x2+2qy2p=x^2+2qy^2, where [][\cdot] is the greatest integer function and x,yZx,y\in\Bbb Z.

Keywords

Cite

@article{arxiv.1401.0493,
  title  = {Congruences for $q^{[p/8]}\pmod p$ II},
  author = {Zhi-Hong Sun},
  journal= {arXiv preprint arXiv:1401.0493},
  year   = {2014}
}

Comments

28 pages. arXiv admin note: substantial text overlap with arXiv:1108.3027

R2 v1 2026-06-22T02:38:21.805Z