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Congruences involving $\binom{4k}{2k}$ and $\binom{3k}k$

Number Theory 2011-08-25 v1 Combinatorics

Abstract

Let pp be a prime greater than 3. In the paper we mainly determine k=0[p/4](4k2k)(1)k\sum_{k=0}^{[p/4]}\binom{4k}{2k}(-1)^k, k=0[p/3](3kk),k=0[p/3](3kk)(1)k\sum_{k=0}^{[p/3]}\binom{3k}k, \sum_{k=0}^{[p/3]}\binom{3k}k(-1)^k and k=0[p/3](3kk)(3)k\sum_{k=0}^{[p/3]}\binom{3k}k(-3)^k modulo pp, where [x][x] is the greatest integer not exceeding xx.

Keywords

Cite

@article{arxiv.1108.4840,
  title  = {Congruences involving $\binom{4k}{2k}$ and $\binom{3k}k$},
  author = {Zhi-Hong Sun},
  journal= {arXiv preprint arXiv:1108.4840},
  year   = {2011}
}

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24 pages