English

Conjectures and results on $x^2$ mod $p^2$ with $4p=x^2+dy^2$

Number Theory 2014-02-21 v9 Combinatorics

Abstract

Given a squarefree positive integer dd, we want to find integers (or rational numbers with denominators not divisible by large primes) a0,a1,a2,a_0,a_1,a_2,\ldots such that for sufficiently large primes pp we have k=0p1akx22p\sum_{k=0}^{p-1}a_k\equiv x^2-2p (mod p2p^2) if 4p=x2+dy24p=x^2+dy^2 (and 4x4\nmid x if d=1d=1), and k=0p1ak0\sum_{k=0}^{p-1}a_k\equiv 0 (mod p2p^2) if (dp)=1(\frac{-d}p)=-1. In this paper we give a survey of conjectures and results on this topic and point out the connection between this problem and series for 1/π1/\pi.

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Cite

@article{arxiv.1103.4325,
  title  = {Conjectures and results on $x^2$ mod $p^2$ with $4p=x^2+dy^2$},
  author = {Zhi-Wei Sun},
  journal= {arXiv preprint arXiv:1103.4325},
  year   = {2014}
}

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