English

Inversions and Longest Increasing Subsequence for $k$-Card-Minimum Random Permutations

Probability 2014-06-17 v1

Abstract

A random nn-permutation may be generated by sequentially removing random cards C1,...,CnC_1,...,C_n from an nn-card deck D={1,...,n}D = \{1,...,n\}. The permutation σ\sigma is simply the sequence of cards in the order they are removed. This permutation is itself uniformly random, as long as each random card CtC_t is drawn uniformly from the remaining set at time tt. We consider, here, a variant of this simple procedure in which one is given a choice between kk random cards from the remaining set at each step, and selects the lowest numbered of these for removal. This induces a bias towards selecting lower numbered of the remaining cards at each step, and therefore leads to a final permutation which is more "ordered" than in the uniform case (i.e. closer to the identity permutation id =(1,2,3,...,n)=(1,2,3,...,n)). We quantify this effect in terms of two natural measures of order: The number of inversions II and the length of the longest increasing subsequence LL. For inversions, we establish a weak law of large numbers and central limit theorem, both for fixed and growing kk. For the longest increasing subsequence, we establish the rate of scaling, in general, and existence of a weak law in the case of growing kk. We also show that the minimum strategy, of selecting the minimum of the kk given choices at each step, is optimal for minimizing the number of inversions in the space of all online kk-card selection rules.

Keywords

Cite

@article{arxiv.1406.3911,
  title  = {Inversions and Longest Increasing Subsequence for $k$-Card-Minimum Random Permutations},
  author = {Nicholas F. Travers},
  journal= {arXiv preprint arXiv:1406.3911},
  year   = {2014}
}

Comments

30 pages, no figures

R2 v1 2026-06-22T04:39:03.533Z