English

Upper bound for the number of spanning forests of regular graphs

Combinatorics 2022-12-09 v3

Abstract

We show that if GG is a dd--regular graph on nn vertices, then the number of spanning forests F(G)F(G) satisfies F(G)dnF(G)\leq d^n. The previous best bound due to Kahale and Schulman gave (d+1/2+O(1/d))n(d+1/2+O(1/d))^n. We also have the more precise conjecture that F(G)1/n(d1)d1(d22d1)d/21.F(G)^{1/n}\leq \frac{(d-1)^{d-1}}{(d^2-2d-1)^{d/2-1}}. If this conjecture is true, then the expression on the right hand side is the best possible.

Keywords

Cite

@article{arxiv.2105.06801,
  title  = {Upper bound for the number of spanning forests of regular graphs},
  author = {Ferenc Bencs and Péter Csikvári},
  journal= {arXiv preprint arXiv:2105.06801},
  year   = {2022}
}

Comments

arXiv admin note: text overlap with arXiv:2105.06798