English

Polynomials with roots in ${\Bbb Q}_p$ for all $p$

Number Theory 2007-05-23 v4

Abstract

Let f(x)f(x) be a monic polynomial in \dZ[x]\dZ[x] with no rational roots but with roots in \dQp\dQ_p for all pp, or equivalently, with roots mod nn for all nn. It is known that f(x)f(x) cannot be irreducible but can be a product of two or more irreducible polynomials, and that if f(x)f(x) is a product of m>1m>1 irreducible polynomials, then its Galois group must be a union of conjugates of mm proper subgroups. We prove that for any m>1m>1, every finite solvable group which is a union of conjugates of mm proper subgroups (where all these conjugates have trivial intersection) occurs as the Galois group of such a polynomial, and that the same result (with m=2m=2) holds for all Frobenius groups. It is also observed that every nonsolvable Frobenius group is realizable as the Galois group of a geometric--i.e. regular-- extension of \dQ(t)\dQ(t).

Keywords

Cite

@article{arxiv.math/0612528,
  title  = {Polynomials with roots in ${\Bbb Q}_p$ for all $p$},
  author = {Jack Sonn},
  journal= {arXiv preprint arXiv:math/0612528},
  year   = {2007}
}

Comments

6 pages, revised to simplify a proof, improve a result, add a remark, and make some minor corrections