English

On determinants involving $(\frac{j+k}p)\pm(\frac{j-k}p)$

Number Theory 2025-04-02 v4

Abstract

Let p=2n+1p=2n+1 be an odd prime. In this paper, we mainly evaluate determinants involving (j+kp)±(jkp)(\frac {j+k}p)\pm(\frac{j-k}p), where (p)(\frac{\cdot}p) denotes the Legendre symbol. When p1(mod4)p\equiv1\pmod4, we determine the characteristic polynomials of the matrices [(j+kp)+(jkp)]1j,kn  and  [(j+kp)(jkp)]1j,kn,\left[\left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)\right]_{1\le j,k\le n}\ \ \text{and}\ \ \left[\left(\frac{j+k}p\right)-\left(\frac{j-k}p\right)\right]_{1\le j,k\le n}, and also establish the general identity \begin{align*} &\ \left|x+\left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)+\left(\frac jp\right)y+\left(\frac kp\right)z+\left(\frac{jk}p\right)w\right|_{1\le j,k\le n} \\=&\ (-p)^{(p-5)/4}\left(\left(\frac{p-1}2\right)^2wx-\left(\frac{p-1}2y-1\right)\left(\frac{p-1}2z-1\right)\right). \end{align*}

Keywords

Cite

@article{arxiv.2409.08213,
  title  = {On determinants involving $(\frac{j+k}p)\pm(\frac{j-k}p)$},
  author = {Deyi Chen and Zhi-Wei Sun},
  journal= {arXiv preprint arXiv:2409.08213},
  year   = {2025}
}

Comments

16 pages. Make Conjecture 1.1 stronger