English

Effective Primality Test for $p2^n+1$, $p$ prime, $n>1$

Number Theory 2018-11-16 v1

Abstract

We develop a simple O((logn)2)O((\log n)^2) test as an extension of Proth's test for the primality for p2n+1p2^n+1, p>2np>2^n. This allows for the determination of large, non-Sierpinski primes pp and the smallest nn such that p2n+1p2^n+1 is prime. If pp is a non-Sierpinski prime, then for all nn where p2n+1p2^n+1 passes the initial test, p2n+1p2^n+1 is prime with 33 as a primitive root or is primover and divides the base 33 Fermat Number, GF(3,n1)GF(3,n-1). We determine the form the factors of any composite overpseudoprime that passes the initial test take by determining the form that factors of GF(3,n1)GF(3,n-1) take.

Keywords

Cite

@article{arxiv.1811.06070,
  title  = {Effective Primality Test for $p2^n+1$, $p$ prime, $n>1$},
  author = {Tejas R. Rao},
  journal= {arXiv preprint arXiv:1811.06070},
  year   = {2018}
}

Comments

3 pages

R2 v1 2026-06-23T05:16:03.607Z