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Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. III

Commutative Algebra 2024-07-09 v1

Abstract

Let II be a squarefree monomial ideal of S=K[x1,,xn]S=K[x_1,\ldots,x_n]. We prove that if hdepth(S/I)8\operatorname{hdepth}(S/I)\leq 8 or n10n\leq 10 then hdepth(I)hdepth(S/I)1\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I)-1.

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Cite

@article{arxiv.2407.04759,
  title  = {Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. III},
  author = {Andreea I. Bordianu and Mircea Cimpoeas},
  journal= {arXiv preprint arXiv:2407.04759},
  year   = {2024}
}

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28 pages