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Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. II

Commutative Algebra 2024-04-09 v1 Combinatorics

Abstract

Let II be a squarefree monomial ideal of S=K[x1,,xn]S=K[x_1,\ldots,x_n]. We prove that if hdepth(S/I)6\operatorname{hdepth}(S/I)\leq 6 of n9n\leq 9 then hdepth(I)hdepth(S/I)\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I), giving a positive answer to a problem putted in arxiv:2403.17078

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Cite

@article{arxiv.2404.04646,
  title  = {Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. II},
  author = {Andreea I. Bordianu and Mircea Cimpoeas},
  journal= {arXiv preprint arXiv:2404.04646},
  year   = {2024}
}

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31 pages