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Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$

Commutative Algebra 2025-01-22 v3 Combinatorics

Abstract

Let II be a monomial ideal of S=K[x1,,xn]S=K[x_1,\ldots,x_n]. We show that the following are equivalent: (i) II is principal, (ii) hdepth(I)=n\operatorname{hdepth}(I)=n, (iii) hdepth(S/I)=n1\operatorname{hdepth}(S/I)=n-1. Assuming that II is squarefree, we prove that if hdepth(S/I)3\operatorname{hdepth}(S/I)\leq 3 or n5n\leq 5 then hdepth(I)hdepth(S/I)+1\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I)+1. Also, we prove that if hdepth(S/I)5\operatorname{hdepth}(S/I)\leq 5 or n7n\leq 7 then then hdepth(I)hdepth(S/I)\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I).

Keywords

Cite

@article{arxiv.2403.17078,
  title  = {Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$},
  author = {Andreea I. Bordianu and Mircea Cimpoeas},
  journal= {arXiv preprint arXiv:2403.17078},
  year   = {2025}
}

Comments

29 pages; there is an overlap with a previous version of arXiv:2310.12339; minor corrections