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A note on the Alon-Saks-Seymour problem

Combinatorics 2026-05-29 v1 Discrete Mathematics

Abstract

Let f(k)f(k) be the maximum possible chromatic number of a graph whose edge set can be partitioned into at most kk complete bipartite graphs. Alon, Saks, and Seymour conjectured that f(k)=k+1f(k)=k+1 for all kk. While the conjecture was verified for k9k \leq 9 by Gao et al., it was disproved by Huang and Sudakov, and further Balodis et al. proved that f(k)2Ω~((logk)2)f(k) \geq 2^{\widetilde{\Omega}((\log k)^2)}. In this note, we give a simple proof of the recursive upper bound f(k+1)f(k)+f(k/4)f(k+1) \leq f(k)+f(\lfloor k/4 \rfloor). Consequently, f(k)2(log2(4k))2/4f(k) \leq 2^{(\log_2 (4k))^2/4} for k1k \geq 1. This improves the previous best known upper bound of Mubayi and Vishwanathan in the exponent by a factor which is asymptotically two. Note that these bounds are sharp up to a lower order factor in the exponent by the result of Balodis et al.

Keywords

Cite

@article{arxiv.2605.28915,
  title  = {A note on the Alon-Saks-Seymour problem},
  author = {Jacob Fox},
  journal= {arXiv preprint arXiv:2605.28915},
  year   = {2026}
}

Comments

2 pages

R2 v1 2026-07-22T07:37:58.043Z