English

On the Firoozbakht's conjecture

General Mathematics 2016-06-07 v2

Abstract

This paper proves Firoozbakht's conjecture using Rosser and Schoenfelds' inequality on the distribution of primes. This inequality is valid for all natural numbers n21{n\geq 21}. Firoozbakht's conjecture states that if pn {p_{n}} and p(n+1){p_{(n+1)}} are consecutive prime numbers, then p(n+1)1/(n+1)<pn1/n{p_{(n+1)}^{1/(n+1)}< p_{n}^{1/n}} for every n1{n\geq 1}. Rosser's inequality for the n{n}th and (n+1){(n+1)}th roots, changes from strictly increasing to strictly decreasing for n21{n\geq 21}. The inequality is considered for n>ee3/2{n>e^{e^{3/2}}}, i.e., n89{n\geq 89}, but since the inequalities for n195340>ee5/2{n\geq 195340>e^{e^{5/2}}}, are also required, these inequalities are explicitly proven as well. Silva has already verified Firoozbakht's conjecture up to pn<4×1018{p_{n}<4 \times 10^{18}}, and the additional theorem is proven here that there is the smallest natural number, m>n1{m>n\geq 1} and pm1/m<pn1/n{p_{m}^{1/m}< p_{n}^{1/n}}. It is also shown that there is a unique one to one function, which maps each element pn{p_n} to each element pn1/n{p_{n}^{1/n}} for every n1{n\geq 1} and 1<pn1/n2{1<p_{n}^{1/n}\leq 2}. Finally, it is proved that there is a strictly decreasing sequence and Firoozbakht's conjecture would be true for all n1{n\geq 1}.

Keywords

Cite

@article{arxiv.1603.08917,
  title  = {On the Firoozbakht's conjecture},
  author = {Ahmad Sabihi},
  journal= {arXiv preprint arXiv:1603.08917},
  year   = {2016}
}

Comments

18 pages. This paper has been refereed for 8 months, revised two times, and edited in a strong journal, but I have withdrawn it due to some reasons and would like to submit to another journal

R2 v1 2026-06-22T13:20:52.452Z