Aut($\Gamma$)=det($M_\Gamma$)
General Mathematics
2018-07-05 v1
Abstract
In this article, we will show that the automorphism group of any hypergraph is essentially equal to the determinant of some matrix over a ring generated from the set of ground points. With this, we are also able to determine whether two graphs are isomorphic.
Cite
@article{arxiv.1807.01580,
title = {Aut($\Gamma$)=det($M_\Gamma$)},
author = {Zhonggan Huang},
journal= {arXiv preprint arXiv:1807.01580},
year = {2018}
}