English

A complete Heyting algebra whose Scott space is non-sober

General Topology 2019-03-05 v1

Abstract

We prove that (1) for any complete lattice LL, the set D(L)\mathcal{D}(L) of all nonempty saturated compact subsets of the Scott space of LL is a complete Heyting algebra (with the reverse inclusion order); and (2) if the Scott space of a complete lattice LL is non-sober, then the Scott space of D(L)\mathcal{D}(L) is non-sober. Using these results and the Isbell's example of a non-sober complete lattice, we deduce that there is a complete Heyting algebra whose Scott space is non-sober, thus give a positive answer to a problem posed by Jung. We will also prove that a T0T_0 space is well-filtered iff its upper space (the set D(X)\mathcal{D}(X) of all nonempty saturated compact subsets of XX equipped with the upper Vietoris topology) is well-filtered, which answers another open problem.

Keywords

Cite

@article{arxiv.1903.00615,
  title  = {A complete Heyting algebra whose Scott space is non-sober},
  author = {Xiaoquan Xu and Xiaoyong Xi and Dongsheng Zhao},
  journal= {arXiv preprint arXiv:1903.00615},
  year   = {2019}
}

Comments

9 pages

R2 v1 2026-06-23T07:56:04.988Z