A complete Heyting algebra whose Scott space is non-sober
General Topology
2019-03-05 v1
Abstract
We prove that (1) for any complete lattice , the set of all nonempty saturated compact subsets of the Scott space of is a complete Heyting algebra (with the reverse inclusion order); and (2) if the Scott space of a complete lattice is non-sober, then the Scott space of is non-sober. Using these results and the Isbell's example of a non-sober complete lattice, we deduce that there is a complete Heyting algebra whose Scott space is non-sober, thus give a positive answer to a problem posed by Jung. We will also prove that a space is well-filtered iff its upper space (the set of all nonempty saturated compact subsets of equipped with the upper Vietoris topology) is well-filtered, which answers another open problem.
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Cite
@article{arxiv.1903.00615,
title = {A complete Heyting algebra whose Scott space is non-sober},
author = {Xiaoquan Xu and Xiaoyong Xi and Dongsheng Zhao},
journal= {arXiv preprint arXiv:1903.00615},
year = {2019}
}
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9 pages