English

Spectral spaces of countable abelian lattice-ordered groups

Rings and Algebras 2017-12-01 v3 Logic

Abstract

A compact topological space X is spectral if it is sober (i.e., every irreducible closed set is the closure of a unique singleton) and the compact open subsets of X form a basis of the topology of X, closed under finite intersections. Theorem. A topological space X is homeomorphic to the spectrum of some countable Abelian {\ell}-group with unit (resp., MV-algebra) iff X is spectral, has a countable basis of open sets, and for any points x and y in the closure of a singleton {z}, either x is in the closure of {y} or y is in the closure of {x}. We establish this result by proving that a countable distributive lattice D with zero is isomorphic to the lattice of all principal ideals of an Abelian {\ell}-group (we say that D is {\ell}-representable) iff for all a, b \in D there are x, y \in D such that a \lor b = a \lor y = b \lor x and x \land y = 0. On the other hand, we construct a non-{\ell}-representable bounded distributive lattice, of cardinality \aleph 1 , with an {\ell}-representable countable L,ω\infty, \omega-elementary sublattice. In particular, there is no characterization, of the class of all {\ell}-representable distributive lattices, in arbitrary cardinality, by any class of L,ω\infty, \omega sentences.

Keywords

Cite

@article{arxiv.1701.03494,
  title  = {Spectral spaces of countable abelian lattice-ordered groups},
  author = {Friedrich Wehrung},
  journal= {arXiv preprint arXiv:1701.03494},
  year   = {2017}
}

Comments

Misprints v2: In Example 7.1, (a-mb)\wedge(b-mc) \leq 0 (i.e., \wedge instead of \vee).In Corollary 8.6, X, Y^-, and Y^+ are just elements of \Op(\mathcal{H}) (not necessarily basic open)

R2 v1 2026-06-22T17:49:05.781Z