Spectral spaces of countable abelian lattice-ordered groups
Abstract
A compact topological space X is spectral if it is sober (i.e., every irreducible closed set is the closure of a unique singleton) and the compact open subsets of X form a basis of the topology of X, closed under finite intersections. Theorem. A topological space X is homeomorphic to the spectrum of some countable Abelian {\ell}-group with unit (resp., MV-algebra) iff X is spectral, has a countable basis of open sets, and for any points x and y in the closure of a singleton {z}, either x is in the closure of {y} or y is in the closure of {x}. We establish this result by proving that a countable distributive lattice D with zero is isomorphic to the lattice of all principal ideals of an Abelian {\ell}-group (we say that D is {\ell}-representable) iff for all a, b D there are x, y D such that a b = a y = b x and x y = 0. On the other hand, we construct a non-{\ell}-representable bounded distributive lattice, of cardinality 1 , with an {\ell}-representable countable L-elementary sublattice. In particular, there is no characterization, of the class of all {\ell}-representable distributive lattices, in arbitrary cardinality, by any class of L sentences.
Cite
@article{arxiv.1701.03494,
title = {Spectral spaces of countable abelian lattice-ordered groups},
author = {Friedrich Wehrung},
journal= {arXiv preprint arXiv:1701.03494},
year = {2017}
}
Comments
Misprints v2: In Example 7.1, (a-mb)\wedge(b-mc) \leq 0 (i.e., \wedge instead of \vee).In Corollary 8.6, X, Y^-, and Y^+ are just elements of \Op(\mathcal{H}) (not necessarily basic open)