English

A bilinear Rubio de Francia inequality for arbitrary rectangles

Classical Analysis and ODEs 2018-08-21 v1

Abstract

Let R\mathscr{R} be a collection of disjoint dyadic rectangles RR with sides parallel to the axes, let πR\pi_R denote the non-smooth bilinear projection onto RR πR(f,g)(x):=1R(ξ,η)f^(ξ)g^(η)e2πi(ξ+η)xdξdη \pi_R (f,g)(x):=\iint \mathbf{1}_{R}(\xi,\eta) \widehat{f}(\xi) \widehat{g}(\eta) e^{2\pi i (\xi + \eta) x} d\xi d\eta and let r>2r>2. We show that the bilinear Rubio de Francia operator associated to R\mathscr{R} given by f,g(RRπR(f,g)r)1/r f,g \mapsto \Big(\sum_{R\in\mathscr{R}} |\pi_{R} (f,g)|^r \Big)^{1/r} is Lp×LqLsL^p \times L^q \rightarrow L^s bounded whenever 1/p+1/q=1/s1/p + 1/q = 1/s, r<p,q<rr'<p,q<r. This extends from squares to rectangles a previous result by the same authors, and as a corollary extends in the same way a previous result from Benea and the first author for smooth projections, albeit in a reduced range.

Cite

@article{arxiv.1808.06534,
  title  = {A bilinear Rubio de Francia inequality for arbitrary rectangles},
  author = {Frédéric Bernicot and Marco Vitturi},
  journal= {arXiv preprint arXiv:1808.06534},
  year   = {2018}
}

Comments

29 pages, 2 figures

R2 v1 2026-06-23T03:38:33.430Z