English

A bilinear Rubio de Francia inequality for arbitrary squares

Classical Analysis and ODEs 2016-02-08 v1

Abstract

We prove the boundedness of a smooth bilinear Rubio de Francia operator associated with an arbitrary collection of squares (with sides parallel to the axes) in the frequency plane(f,g)(_ωΩ_R2f^(ξ)g^(η)Φ_ω(ξ,η)e2πix(ξ+η)dξdηr)1/r,\left(f, g \right)\mapsto \left( \sum\_{\omega \in \Omega}\left| \int\_{\mathbb{R}^2} \hat{f}(\xi) \hat{g}(\eta) \Phi\_{\omega}(\xi, \eta) e^{2 \pi i x\left(\xi+\eta \right)} d \xi d \eta\right|^r \right)^{1/r}, provided r\textgreater2r\textgreater{}2. More exactly, we show that the above operator maps Lp×LqLsL^p \times L^q \to L^s whenever p,q,sp, q, s' are in the "local LrL^{r'}" range, i.e. 1p+1q+1s=1\displaystyle \frac{1}{p}+\frac{1}{q}+\frac{1}{s'}=1, 01p,1q\textless1r\displaystyle0 \leq \frac{1}{p}, \frac{1}{q} \textless{}\frac{1}{r'}, and 1s\textless1r\displaystyle\frac{1}{s'}\textless{}\frac{1}{r'}. Note that we allow for negative values of ss', which correspond to quasi-Banach spaces LsL^s.

Keywords

Cite

@article{arxiv.1602.01948,
  title  = {A bilinear Rubio de Francia inequality for arbitrary squares},
  author = {Cristina Benea and Frederic Bernicot},
  journal= {arXiv preprint arXiv:1602.01948},
  year   = {2016}
}