$(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube
Number Theory
2016-12-28 v1
Authors:
Chuan Ze Niu
Abstract
For a positive integer n, define Cn=k=1∏n(k3+1). In this paper we prove that there are no cubes in the integer sequence Cn, n=1,2,⋯.
Cite
@article{arxiv.1612.08158,
title = {$(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube},
author = {Chuan Ze Niu},
journal= {arXiv preprint arXiv:1612.08158},
year = {2016}
}
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