English

$(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube

Number Theory 2016-12-28 v1

Abstract

For a positive integer n,n, define Cn=k=1n(k3+1).C_n=\prod_{k=1}^n(k^3+1). In this paper we prove that there are no cubes in the integer sequence Cn, n=1,2,.C_n,~n=1,2,\cdots.

Cite

@article{arxiv.1612.08158,
  title  = {$(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube},
  author = {Chuan Ze Niu},
  journal= {arXiv preprint arXiv:1612.08158},
  year   = {2016}
}
R2 v1 2026-06-22T17:33:51.702Z