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The concordance genus of a knot is the least genus of any knot in its concordance class. Although difficult to compute, it is a useful invariant that highlights the distinction between the three-genus and four-genus. In this paper we define…

Geometric Topology · Mathematics 2013-10-18 M. Kate Kearney

In this paper we study $k$-noncrossing RNA structures with minimum arc-length 4 and at most $k-1$ mutually crossing bonds. Let ${\sf T}_{k}^{[4]}(n)$ denote the number of $k$-noncrossing RNA structures with arc-length $\ge 4$ over $n$…

Combinatorics · Mathematics 2008-07-04 Hillary S. W. Han , Christian M. Reidys

In previous papers, the author realized the following principle for many knot theories: if a knot diagram is complicated enough then it reproduces itself, i.e., is a subdiagram of any other diagram equivalent to it. This principle is…

Geometric Topology · Mathematics 2015-02-03 Vassily Olegovich Manturov

Using the Huynh and Le quantum determinant description of the colored Jones polynomial, we construct a new combinatorial description of the colored Jones polynomial in terms of walks along a braid. We then use this description to show that…

Geometric Topology · Mathematics 2015-03-17 Cody Armond

We construct an infinite collection of knots with the property that any knot in this family has $n$-string essential tangle decompositions for arbitrarily high $n$.

Geometric Topology · Mathematics 2017-05-19 João Miguel Nogueira

We give asymptotically sharp upper bounds for the Khovanov width and the dealternation number of positive braid links, in terms of their crossing number. The same braid-theoretic technique, combined with Ozsv\'ath, Stipsicz, and Szab\'o's…

Geometric Topology · Mathematics 2020-03-26 Sebastian Baader , Peter Feller , Lukas Lewark , Raphael Zentner

We investigate a generalization of the bondage number of a graph called the \textit{$k\,$-synchronous bondage number}. The $k\,$-synchronous bondage number of a graph is the smallest number of edges that, when removed, increases the…

Combinatorics · Mathematics 2022-08-17 Rey Anaya , Alvaro Belmonte , Nathan Shank , Elise Sinani , Bryan Walker

Experimental work suggests that the Seifert genus of a knot grows linearly with respect to the crossing number of the knot. In this article, we use a billiard table model for $2$-bridge or rational knots to show that the average genus of a…

Geometric Topology · Mathematics 2025-08-19 Moshe Cohen , Adam M. Lowrance

Given a knot in $S^3$, one can associate to it a surface diffeomorphism in two different ways. First, an arbitrary knot in $S^{3}$ can be represented by braids, which can be thought of as diffeomorphisms of punctured disks. Second, if the…

We prove a conjecture due to Makanin: if a and b are elements of the Artin braid group B_n such that a^k=b^k for some nonzero integer k, then a and b are conjugate. The proof involves the Nielsen-Thurston classification of braids.

Geometric Topology · Mathematics 2014-10-01 Juan Gonzalez-Meneses

We study the representations of the commutator subgroup K_{n} of the braid group B_{n} into a finite group . This is done through a symbolic dynamical system. Some experimental results enable us to compute the number of subgroups of K_{n}…

Dynamical Systems · Mathematics 2007-05-23 Abdelouahab Arouche

We study certain linear representations of the knot group that induce augmentations of knot contact homology. This perspective on augmentations enhances our understanding of the relationship between the augmentation polynomial and the…

Geometric Topology · Mathematics 2014-08-28 Christopher Cornwell

The ropelength of a knot is the quotient of its length and its thickness, the radius of the largest embedded normal tube around the knot. We prove existence and regularity for ropelength minimizers in any knot or link type; these are…

Geometric Topology · Mathematics 2015-06-26 Jason Cantarella , Rob Kusner , John M Sullivan

The trunk of a knot in $S^3$, defined by Makoto Ozawa, is a measure of geometric complexity similar to the bridge number or width of a knot. We prove that for any two knots $K_1$ and $K_2$, we have $tr(K_1 \# K_2) =…

Geometric Topology · Mathematics 2016-08-02 Derek Davies , Alexander Zupan

It has been conjectured that for knots $K$ and $K'$ in $S^3$, $w(K#K')= w(K)+w(K')-2$. Scharlemann and Thompson have proposed potential counterexamples to this conjecture. For every $n$, they proposed a family of knots ${K^n_i}$ for which…

Geometric Topology · Mathematics 2009-08-31 Ryan Blair , Maggy Tomova

For an integer $n$, write $X_n(K)$ for the 4-manifold obtained by attaching a 2-handle to the 4-ball along the knot $K\subset S^3$ with framing $n$. It is known that if $n< \overline{\text{tb}}(K)$, then $X_n(K)$ admits the structure of a…

Geometric Topology · Mathematics 2017-10-24 Thomas E. Mark , Lisa Piccirillo , Faramarz Vafaee

We have the generating function which determines the number of $2$-bridge knot groups admitting epimorphisms onto the knot group of a given $2$-bridge knot, in terms of crossing number. In this paper, we will refine this formula by taking…

Geometric Topology · Mathematics 2020-10-15 Masaaki Suzuki

We characterise positive braid links with positive Seifert form via a finite number of forbidden minors. From this we deduce a one-to-one correspondence between prime positive braid links with positive Seifert form and simply laced Dynkin…

Geometric Topology · Mathematics 2012-11-21 Sebastian Baader

A Boolean network (BN) is called observable if any initial state can be uniquely determined from the output sequence. In the existing literature on observability of BNs, there is almost no research on the relationship between the number of…

Systems and Control · Electrical Eng. & Systems 2024-07-29 Liangjie Sun , Wai-Ki Ching , Tatsuya Akutsu

Given a knot K in S^3, let u^-(K) (respectively, u^+(K)) denote the minimum number of negative (respectively, positive) crossing changes among all unknotting sequences for K. We use knot Floer homology to construct the invariants l^-(K),…

Geometric Topology · Mathematics 2021-01-06 Akram Alishahi , Eaman Eftekhary