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We prove the non-left-orderability of the fundamental group of the $n$-th fold cyclic branched cover of the pretzel knot $P(3,-3,-2k-1)$ for all integers $k$ and $n\ge 1$. These $3$-manifolds are $L$-spaces discovered by Issa and Turner.

Geometric Topology · Mathematics 2021-06-30 Lin Li , Zipei Nie

The main goal of this paper is to prove that for odd free knots - that is free knots with all odd crossings - the problem of sliceness (the existence of a spanning disc) has an explicit answer based on the pairing of the knot diagram…

Geometric Topology · Mathematics 2017-07-20 Denis Fedoseev , Vassily Manturov

We use technology from sutured manifold theory and the theory of Heegaard splittings to relate genus reducing crossing changes on knots in S^3 to twists on surfaces arising in circular Heegaard splittings for knot complements. In a separate…

Geometric Topology · Mathematics 2012-10-23 Alexander Coward

Let $M$ be a connected, closed, oriented three-manifold and $K$, $L$ two rationally null-homologous oriented simple closed curves in $M$. We give an explicit algorithm for computing the linking number between $K$ and $L$ in terms of a…

Geometric Topology · Mathematics 2021-07-09 Patricia Cahn , Alexandra Kjuchukova

In a series of papers the authors proved that twisted Alexander polynomials detect fibered 3-manifolds, and they showed that this implies that a closed 3-manifold N is fibered if and only if S^1 x N is symplectic. In this note we summarize…

Geometric Topology · Mathematics 2010-01-05 Stefan Friedl , Stefano Vidussi

We consider the Alexander polynomial of a plane algebraic curve twisted by a linear representation. We show that it divides the product of the polynomials of the singularity links, for unitary representations. Moreover, their quotient is…

Geometric Topology · Mathematics 2007-05-23 Jose Ignacio Cogolludo , Vincent Florens

For n >1, if the Seifert form of a knotted 2n-1 sphere K in S^{2n+1} has a metabolizer, then the knot is slice. Casson and Gordon proved that this is false in dimension three (n = 1). However, in the three dimensional case it is true that…

Geometric Topology · Mathematics 2007-05-23 Charles Livingston

We show that every strongly-cyclic branched covering of a (1,1)-knot is a Dunwoody manifold. This result, together with the converse statement previously obtained by Grasselli and Mulazzani, proves that the class of Dunwoody manifolds…

Geometric Topology · Mathematics 2007-05-23 Alessia Cattabriga , Michele Mulazzani

For $\ell >1$, we develop $L^{(2)}$-signature obstructions for $(4\ell-3)$-dimensional knots with metabelian knot groups to be doubly slice. For each $\ell>1$, we construct an infinite family of knots on which our obstructions are non-zero,…

Geometric Topology · Mathematics 2019-09-19 Patrick Orson , Mark Powell

We study $\mathrm{SL}_2(\mathbb{F})$-character varieties of knots over algebraically closed fields $\mathbb{F}$. We give a sufficient condition in terms of the double branched cover of a $2$-bridge knot (or, equivalently, of its Alexander…

Geometric Topology · Mathematics 2019-05-20 Luisa Paoluzzi , Joan Porti

We show that for genus one knots the Alexander polynomial and the homology of the double cover branching over the knot provide obstructions to cosmetic crossings. As an application we prove the nugatory crossing conjecture for the…

Geometric Topology · Mathematics 2011-07-12 Cheryl Balm , Efstratia Kalfagianni

The group of a nontrivial knot admits a finite permutation representation such that the corresponding twisted Alexander polynomial is not a unit.

Geometric Topology · Mathematics 2009-05-21 Daniel S Silver , Susan G Williams

Let N be a closed, oriented 3-manifold. A folklore conjecture states that $S^{1} \times N$ admits a symplectic structure if and only if $N$ admits a fibration over the circle. We will prove this conjecture in the case when N is irreducible…

Geometric Topology · Mathematics 2018-12-24 Stefan Friedl , Stefano Vidussi

Twisted Alexander invariants of knots are well-defined up to multiplication of units. We get rid of this multiplicative ambiguity via a combinatorial method and define normalized twisted Alexander invariants. We then show that the…

Geometric Topology · Mathematics 2015-07-07 Takahiro Kitayama

We show that if the fundamental group of the complement of a rationally homologically fibered knot in a rational homology 3-sphere is bi-orderable, then its Alexander polynomial has at least one positive real root. Our argument can be…

Geometric Topology · Mathematics 2017-04-10 Tetsuya Ito

In this paper we study the homeomorphisms of the disk that are liftable with respect to a simple branched covering. Since any such homeomorphism maps the branch set of the covering onto itself and liftability is invariant up to isotopy…

Geometric Topology · Mathematics 2007-05-23 Michele Mulazzani , Riccardo Piergallini

We construct many examples of non-slice knots in 3-space that cannot be distinguished from slice knots by previously known invariants. Using Whitney towers in place of embedded disks, we define a geometric filtration of the 3-dimensional…

Geometric Topology · Mathematics 2007-05-23 Tim D. Cochran , Kent E. Orr , Peter Teichner

This paper provides a construction of a quantum statistical mechanical system associated to knots in the 3-sphere and cyclic branched coverings of the 3-sphere, which is an analog, in the sense of arithmetic topology, of the Bost-Connes…

Mathematical Physics · Physics 2017-02-01 Matilde Marcolli , Yujie Xu

Some generalizations and variations of the Fintushel-Stern rim surgery are known to produce smoothly knotted surfaces. We show that if the fundamental groups of their complements are cyclic, then these surfaces are topologically unknotted.…

Geometric Topology · Mathematics 2008-10-21 Hee Jung Kim , Daniel Ruberman

The primary objects of study in the ``knot theory of complex plane curves'' are C-links: links (or knots) cut out of a 3-sphere in the complex plane by complex plane transverse and totally tangential. Transverse C-links are naturally…

Geometric Topology · Mathematics 2007-05-23 Lee Rudolph
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