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Related papers: Profinite commensurability of S-arithmetic groups

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By arithmeticity and superrigidity, a commensurability class of lattices in a higher rank Lie group is defined by a unique algebraic group over a unique number subfield of $\mathbb{R}$ or $\mathbb{C}$. We prove an adelic version of…

Group Theory · Mathematics 2021-09-22 Holger Kammeyer , Steffen Kionke

We identify the simple algebraic groups over number fields that are, in a suitable sense, determined by their finite adele points. Assuming CSP and Grothendieck rigidity, our results essentially characterize higher rank arithmetic groups…

Group Theory · Mathematics 2026-05-06 Adrian Baumann , Holger Kammeyer

We define the profinite completion of a C*-algebra, which is a pro-C*-algebra, as well as the pro-C*-algebra of a profinite group. We show that the continuous representations of the pro-C*-algebra of a profinite group correspond to the…

Operator Algebras · Mathematics 2012-04-23 Rachid El Harti , N. Christopher Phillips , Paulo R. Pinto

We show that the covolume of an irreducible lattice in a higher rank semisimple Lie group with the congruence subgroup property is determined by the profinite completion. Without relying on CSP, we additionally show that volume is a…

Group Theory · Mathematics 2024-12-18 Holger Kammeyer , Steffen Kionke , Ralf Köhl

We survey recent work ranging around the question in how far a group, or a property of a group, is determined by the set of finite quotient groups. Our focus lies on $S$-arithmetic groups, branch groups, and their relatives.

Group Theory · Mathematics 2025-06-11 Holger Kammeyer , Steffen Kionke

We investigate the ability of a free pro-$\CC$ group of infinite rank to abstractly solve abstract embedding problems, and conclude that for some varieties $\CC$, the profinite completion of any order, of a free pro-$\CC$ group of infinite…

Group Theory · Mathematics 2023-01-31 Tamar Bar-On

Two finitely generated groups have the same set of finite quotients if and only if their profinite completions are isomorphic. Consider the map which sends (the isomorphism class of) an S-arithmetic group to (the isomorphism class of) its…

Group Theory · Mathematics 2011-10-25 Menny Aka

We prove a characterization of profinite algebras, i.e., topological algebras that are isomorphic to a projective limit of finite discrete algebras. In general profiniteness concerns both the topological and algebraic characteristics of a…

Logic · Mathematics 2020-08-25 Friedrich Martin Schneider , Jens Zumbrägel

In this paper we initiate a systematic study of the abstract commensurators of profinite groups. The abstract commensurator of a profinite group $G$ is a group $Comm(G)$ which depends only on the commensurability class of $G$. We study…

Group Theory · Mathematics 2011-07-22 Yiftach Barnea , Mikhail Ershov , Thomas Weigel

Let $k$ be a number field and $S$ a finite set of places of $k$ containing the archimedean ones. We count the number of algebraic points of bounded height whose coordinates lie in the ring of $S$-integers of $k$. Moreover, we give an…

Number Theory · Mathematics 2014-09-12 Fabrizio Barroero

A notion of arithmetic similarity between number fields is defined by requiring equality of some arithmetic statistics over all but finitely many rational primes. The exceptional set is empty in all previously studied cases, but existing…

Number Theory · Mathematics 2025-05-05 Shaver Phagan

We investigate the algebra of an ample groupoid, introduced by Steinberg, over a semifield S. In particular, we obtain a complete characterization of congruence-simpleness for Steinberg algebras of second-countable ample groupoids,…

Rings and Algebras · Mathematics 2021-09-10 Tran Giang Nam , Jens Zumbrägel

Profinite congruences on profinite algebras determining profinite quotients are difficult to describe. In particular, no constructive description is known of the least profinite congruence containing a given binary relation on the algebra.…

Group Theory · Mathematics 2020-03-09 J. Almeida , O. Klíma

Although $S_\infty$ (the group of all permutations of $\mathbb{N}$) is size continuum, both it and its closed subgroups can be presented as the set of paths through a countable tree. The subgroups of $S_\infty$ that can be presented this…

Logic · Mathematics 2025-08-08 Jason Block

It is proved that the profinite completion of the mapping class group Mod (g,n) of a surface of genus g with n boundary components is isomorphic to such of the arithmetic group GL(6g-6+2n, Z). We establish a relation between the normal…

Number Theory · Mathematics 2020-04-10 Igor Nikolaev

By classifying $S$-maximal amenable subgroups of algebraic groups over a global field of characteristic zero, we obtain a complete classification of maximal amenable subgroups up to commensurability in the respective arithmetic groups.…

Group Theory · Mathematics 2022-10-21 Vadim Alekseev , Alessandro Carderi

Let $G$ be a group and let $K$ be a commensurated subgroup of $G$. Then there is a totally disconnected, locally compact (t.d.l.c.) group $\hat{G}_K$ that contains the profinite completion of $K$ as an open compact subgroup and also…

Group Theory · Mathematics 2015-09-03 Colin D. Reid

In this article we calculate the profinite genus of the fundamental group of a $n$-dimensional compact flat manifold $X$ with holonomy group of prime order. As consequence, we prove that if $n\leq 21$, then $X$ is determined among all…

Group Theory · Mathematics 2020-06-23 Genildo de Jesus Nery

A group is $\textit{finitely axiomatizable}$ (FA) in a class $\mathcal{C}$ if it can be determined up to isomorphism within $\mathcal{C}$ by a sentence in the first-order language of group theory. We show that profinite groups of various…

Group Theory · Mathematics 2021-05-25 Andre Nies , Dan Segal , Katrin Tent

There has been much recent interest into those properties of a 3-manifold determined by the profinite completion of its fundamental group. In this paper we give readily computable criteria specifying precisely when two orientable graph…

Geometric Topology · Mathematics 2017-03-16 Gareth Wilkes
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