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Fraenkel and Simpson showed that the number of distinct squares in a word of length n is bounded from above by 2n, since at most two distinct squares have their rightmost, or last, occurrence begin at each position. Improvements by Ilie to…

Formal Languages and Automata Theory · Computer Science 2017-08-23 F. Blanchet-Sadri , S. Osborne

Abelian string matching problems are becoming an object of considerable interest in last years. Very recently, Alatabbi et al. \cite{AILR2015} presented the first solution for the longest common Abelian factor problem for a pair of strings,…

Data Structures and Algorithms · Computer Science 2015-03-12 Szymon Grabowski

A word is cubefree if it contains no non-empty subword of the form xxx. A morphism h : Sigma^* -> Sigma^* is k-uniform if h(a) has length k for all a in Sigma. A morphism is cubefree if it maps cubefree words to cubefree words. We show that…

Combinatorics · Mathematics 2009-04-14 James Currie , Narad Rampersad

We generalise our earlier work on the number of squares in binary recurrence sequences, $\left\{ y_{k} \right\}_{k \geq -\infty}$. In the notation of our previous papers, here we consider the case when $N_{\alpha}$ is any negative integer…

Number Theory · Mathematics 2025-04-10 Paul M Voutier

In combinatorics on words, a word $w$ over an alphabet $\Sigma$ is said to avoid a pattern $p$ over an alphabet $\Delta$ if there is no factor $f$ of $w$ such that $f=h(p)$ where $h:\Delta^*\to\Sigma^*$ is a non-erasing morphism. A pattern…

Combinatorics · Mathematics 2022-03-02 Antoine Domenech , Pascal Ochem

A word is square-free if it does not contain a nonempty word of the form $XX$ as a factor. A famous 1906 result of Thue asserts that there exist arbitrarily long square-free words over a $3$-letter alphabet. We study square-free words with…

Combinatorics · Mathematics 2022-09-20 Michał Dębski , Jarosław Grytczuk , Bartłomiej Pawlik

In this paper we consider the problem of computing the longest common abelian factor (LCAF) between two given strings. We present a simple $O(\sigma~ n^2)$ time algorithm, where $n$ is the length of the strings and $\sigma$ is the alphabet…

Data Structures and Algorithms · Computer Science 2015-03-03 Ali Alatabbi , Costas S. Iliopoulos , Alessio Langiu , M. Sohel Rahman

I present a recursive formula for calculating the number of abelian squares of length $n+n$ over an alphabet of size $d$. The presented formula is similar to a previously known formula but has substantially lower complexity when $d\gg n$.

Combinatorics · Mathematics 2022-03-23 Ryan S. Bennink

A word contains a \emph{half-flip} if it contains non-empty factors $uv$ and $vu$ where $|u|=|v|$. Fici reports a non-constructive proof of the existence of an infinite word over a finite alphabet avoiding half-flips and asks for the size…

Combinatorics · Mathematics 2026-05-20 Pascal Ochem

An abelian square is a string of length 2n where the last n symbols form a permutation of the first n symbols. In this note we count the number of abelian squares and give an asymptotic estimate of this quantity.

Combinatorics · Mathematics 2008-08-01 L. B. Richmond , J. Shallit

We find finite-state recurrences to enumerate the words on the alphabet $[n]^r$ which avoid the patterns 123 and $1k(k-1)\dots2$, and, separately, the words which avoid the patterns 1234 and $1k(k-1)\dots2$.

Combinatorics · Mathematics 2019-01-29 Yonah Biers-Ariel

For every pattern $p$ over the alphabet $\{x,y,x^R,y^R\}$, we specify the least $k$ such that $p$ is $k$-avoidable.

Combinatorics · Mathematics 2015-08-24 James D. Currie , Philip Lafrance

Twins in a finite word are formed by a pair of identical subwords placed at disjoint sets of positions. We investigate the maximum length of twins in a random word over a $k$-letter alphabet. The obtained lower bounds for small values of…

Combinatorics · Mathematics 2023-04-25 Andrzej Dudek , Jarosław Grytczuk , Andrzej Ruciński

A word is level if each letter appears in it the same number of times, plus or minus 1. We give a complete characterization of the lengths for which level ternary circular square-free words exist. Key words: combinatorics on words, circular…

Combinatorics · Mathematics 2020-05-21 James D. Currie , Jesse T. Johnson

In combinatorics on words, a word $w$ over an alphabet $\Sigma$ is said to avoid a pattern $p$ over an alphabet $\Delta$ if there is no factor $f$ of $w$ such that $f=h(p)$ where $h:\Delta^*\to\Sigma^*$ is a non-erasing morphism. A pattern…

Discrete Mathematics · Computer Science 2015-10-08 Pascal Ochem

A large family of words must contain two words that are similar. We investigate several problems where the measure of similarity is the length of a common subsequence. We construct a family of n^{1/3} permutations on n letters, such that…

Combinatorics · Mathematics 2015-03-03 Boris Bukh , Lidong Zhou

We consider words over a binary alphabet. A word $w$ is overlap-free if it does not have factors (blocks of consecutive letters) of the form $uvuvu$ for nonempty $u$. Let $M(w)$ denote the number of positions that are middle positions of…

Combinatorics · Mathematics 2021-08-11 Tero Harju

We investigate the avoidability of unary patterns of size of four with morphic permutations. More precisely, we show that, for the positive integers $i,j,k$, the sizes of the alphabets over which a pattern $x \pi ^ {i} (x) \pi^{j}(x)…

Combinatorics · Mathematics 2019-03-25 Kamellia Reshadi

Two strings x and y are said to be Abelian equivalent if x is a permutation of y, or vice versa. If a string z satisfies z = xy with x and y being Abelian equivalent, then z is said to be an Abelian square. If a string w can be factorized…

Data Structures and Algorithms · Computer Science 2018-01-29 Shiho Sugimoto , Naoki Noda , Shunsuke Inenaga , Hideo Bannai , Masayuki Takeda

Brandenburg and (implicitly) Dejean introduced the concept of repetition threshold: the smallest real number alpha such that there exists an infinite word over a k-letter alphabet that avoids beta-powers for all beta>alpha. We generalize…

Combinatorics · Mathematics 2007-05-23 Lucian Ilie , Jeffrey Shallit