English

Zero-sum $K_m$ over $\mathbb{Z}$ and the story of $K_4$

Combinatorics 2017-09-01 v1

Abstract

We prove the following results solving a problem raised in [Y. Caro, R. Yuster, On zero-sum and almost zero-sum subgraphs over Z\mathbb{Z}, Graphs Combin. 32 (2016), 49--63]. For a positive integer m2m\geq 2, m4m\neq 4, there are infinitely many values of nn such that the following holds: There is a weighting function f:E(Kn){1,1}f:E(K_n)\to \{-1,1\} (and hence a weighting function f:E(Kn){1,0,1}f: E(K_n)\to \{-1,0,1\}), such that eE(Kn)f(e)=0\sum_{e\in E(K_n)}f(e)=0 but, for every copy HH of KmK_m in KnK_n, eE(H)f(e)0\sum_{e\in E(H)}f(e)\neq 0. On the other hand, for every integer n5n\geq 5 and every weighting function f:E(Kn){1,1}f:E(K_n)\to \{-1,1\} such that eE(Kn)f(e)(n2)h(n)|\sum_{e\in E(K_n)}f(e)|\leq \binom{n}{2}-h(n), where h(n)=2(n+1)h(n)=2(n+1) if n0n \equiv 0 (mod 44) and h(n)=2nh(n)=2n if n≢0n \not\equiv 0 (mod 44), there is always a copy HH of K4K_4 in KnK_n for which eE(H)f(e)=0\sum_{e\in E(H)}f(e)=0, and the value of h(n)h(n) is sharp.

Keywords

Cite

@article{arxiv.1708.09777,
  title  = {Zero-sum $K_m$ over $\mathbb{Z}$ and the story of $K_4$},
  author = {Yair Caro and Adriana Hansberg and Amanda Montejano},
  journal= {arXiv preprint arXiv:1708.09777},
  year   = {2017}
}