English

Weierstrass Sigma Function Coefficients Divisibility Hypothesis

Complex Variables 2017-01-11 v2 Algebraic Topology Combinatorics

Abstract

We consider the coefficients in the series expansion at zero of the Weierstrass sigma function σ(z)=zi,j0ai,j(4i+6j+1)!(g2z42)i(2g3z6)j. \sigma(z) = z \sum_{i, j \geqslant 0} {a_{i,j} \over (4 i + 6 j + 1)!} \left({g_2 z^4 \over 2}\right)^i \left(2 g_3 z^6\right)^j. We have ai,jZa_{i,j} \in \mathbb{Z}. We present the divisibility Hypothesis for the integers ai,ja_{i,j} \begin{align*} \nu_2(a_{i,j}) &= \nu_2((4i + 6j + 1)!) - \nu_2(i!) - \nu_2(j!) - 3 i - 4 j, & \nu_3(a_{i,j}) &= \nu_3((4i + 6j + 1)!) - \nu_3(i!) - \nu_3(j!) - i - j. \end{align*} If this conjecture holds, then σ(z)\sigma(z) is a Hurwitz series over the ring Z[g22,6g3]\mathbb{Z}[{g_2 \over 2}, 6 g_3].

Keywords

Cite

@article{arxiv.1701.00848,
  title  = {Weierstrass Sigma Function Coefficients Divisibility Hypothesis},
  author = {Elena Yu. Bunkova},
  journal= {arXiv preprint arXiv:1701.00848},
  year   = {2017}
}

Comments

5 pages, 4 tables

R2 v1 2026-06-22T17:40:28.041Z