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Unconditional convergence of the differences of Fej\'er kernels on $L^2(\mathbb{R})$

Classical Analysis and ODEs 2022-06-09 v6

Abstract

Let Kn(x)K_n(x) denote the Fej\'er kernel given by Kn(x)=j=nn(1jn+1)eijxK_n(x)=\sum_{j=-n}^n\left(1-\frac{|j|}{n+1}\right)e^{-ijx} and let σnf(x)=(Knf)(x)\sigma_nf(x)=(K_n\ast f)(x), where as usual fgf\ast g denotes the convolution of ff and gg. Let the sequence {nk}\{n_k\} be lacunary. Then the series Gf(x)=k=1(σnk+1f(x)σnkf(x))\mathcal{G}f(x)=\sum_{k=1}^\infty \left(\sigma_{n_{k+1}}f(x)-\sigma_{n_k}f(x)\right) converges unconditionally for all fL2(R)f\in L^2(\mathbb{R}). Let (nk)(n_k) be a lacunary sequence, and {ck}k=1\{c_k\}_{k=1}^\infty \in \ell^\infty. Define Rf(x)=k=1ck(σnk+1f(x)σnkf(x)).\mathcal{R}f(x)=\sum_{k=1}^\infty c_k\left(\sigma_{n_{k+1}}f(x)-\sigma_{n_k}f(x)\right). Then there exists a constant C>0C>0 such that Rf2Cf2\|\mathcal{R}f\|_2\leq C\|f\|_2 for all fL2(R)f\in L^2(\mathbb{R}), i.e., Rf\mathcal{R}f is of strong type (2,2)(2,2). As a special case it follows that Gf\mathcal{G}f also is of strong type (2,2)(2,2).

Keywords

Cite

@article{arxiv.2101.03910,
  title  = {Unconditional convergence of the differences of Fej\'er kernels on $L^2(\mathbb{R})$},
  author = {Sakin Demir},
  journal= {arXiv preprint arXiv:2101.03910},
  year   = {2022}
}

Comments

This is a revised version of the present paper